The equation for calculating heat energy is q=mCpΔT, where q is the heat variable, m is the mass of the object, Cp is the specific heat constant and ΔT is the temperature change.
Energy Loss from Inelastic CollisionsThe inelastic collisions of electrons moving through a conductor are the cause of resistance. This heat dissipation in the lattice, called Joule heating, is the source of power dissipation in a resistor.
Watts (
W) to BTUs per hour (BTU/hr) power
conversion calculator and how to
convert.
Watts to BTU/hr conversion table.
| Power (watt) | Power (BTU/hr) |
|---|
| 1 W | 3.412142 BTU/hr |
| 10 W | 34.121416 BTU/hr |
| 100 W | 341.214163 BTU/hr |
| 1000 W | 3412.141633 BTU/hr |
To calculate the wattage requirement to heat steel, use the following equation:
- Watts = 0.05 x Lbs of Steel x ΔT (in °F) / Heat-Up Time (in hrs)
- Watts = 3.1 x Gallons x ΔT (in °F) / Heat-Up Time (in hrs)
- Watts = 165 x Gallons Per Minute X ΔT (in °F)
- Watts = 1.35 x Gallons x ΔT (in °F) / Heat-Up Time (in hrs)
1. heat dissipation - dissipation of heat. chilling, cooling, temperature reduction - the process of becoming cooler; a falling temperature.
- Calculate the power loss in Resistor by P= I^2* R.
- multiply with time T for watt seconds i.e joules.
- 1 joule is 1 watt second.
- divide it by 4.2 to get calories of heat.
The resistor consumes power of voltage *current . This is called power consumption. After consuming the power the resistor gives out the consumed power as heat. This is called power dissipation.
A standard space heater provides approximately 5,100 BTUs, or 1,500 watts. That means that a standard size space heater is more than sufficient for a room with 144 square feet.
Size and Ceiling Height
| Area To Be Cooled (square feet) | Capacity Needed (BTUs per hour) |
|---|
| 400 to 450 | 10,000 |
| 450 to 550 | 12,000 |
| 550 to 700 | 14,000 |
| 700 to 1,000 | 18,000 |
Determining the Heat Output of a Complete System
- Add up the load power of all of your IT equipment.
- Use the following formula for a UPS system with a battery: (0.04 x Power system rating) + (0.05 x Total IT load power).
Rule of thumb.Rules of thumb have be used for decades when sizing HVAC systems. For example, one commonly used rule of thumb for general office areas is that the cooling load is 200-300 square feet of floor area per ton of cooling. For data centers, the cooling load is 150-300 square feet per ton of cooling.
Multiply your square footage by 20 BTUs to get a general estimate. Typically, plan to purchase a heating or cooling unit with 20 BTUs for every square foot of space you have.
Server rooms need more cooling power to keep the temperature down and prevent the server from overheating. If your facility's air conditioning system is not sufficient in keeping that temperature range in the server room additional units are necessary to keep your business running smoothly.
To effectively calculate what the BTU output for any room is, you have to start by getting a tape measure and measuring the height of the room, the width of the room, the length of the room and then finally the size of the window area (that's the length by width of a window in m²).
An HVAC Load Calculation is a mathematical process for measuring several aspects of a building in order to determine the best size, application and style of HVAC system.
Uninterruptible power supplies are part of an electrical circuit. Whenever current is either switched or transmitted through a cable or other material, heat is generated through power loss. An uninterruptible power supply (UPS) system specification will often give two figures for the heat-loss.
Add together all the wattages for Servers, Switches, Routers and multiply by 3.5. Take the total wattage of the lighting and multiply by 4.25. Add all the BTUs together. This is the amount of cooling required so you need one or more air conditioning units to handle that amount of heat.
The heating load is the amount of heat energy that would need to be added to a space to maintain the temperature in an acceptable range. The cooling load is the amount of heat energy that would need to be removed from a space (cooling) to maintain the temperature in an acceptable range.
Immersion cooling is an IT cooling practice by which IT components and other electronics, including complete servers, are submerged in a thermally conductive dielectric liquid or coolant. Heat is removed from the system by circulating liquid into direct contact with hot components, then through cool heat exchangers.
Multiply the number of amps by the number of volts to obtain the number of watts in the circuit. The equation W = A x V shows this relationship where W is the wattage, A is the amperage and V is the voltage. This example assumes a voltage of 110 volts and an amperage of 0.91 amps.
Realistically, the maximum power under normal operating conditions will be around 650 watts. Heat output is measured in British Thermal Units (BTUs) - 1kw/hr = 3412 BTU/h or 1000 BTU/h is around 293W. Based on the 754 watt figure, BTUs/hr = (754 watts * 3600) / 1054 = 2577 BTUs per hour, per server.
Thus at most a properly functioning computer will use 420W = 1433 BTU/hr. But of course that is a maximum. You rarely would need a full 300W from your power supply.
Over 12 hours of peak intensity use, the computer will generate 246W*12*3600 s = 10.627 Megajoules of energy. Like most electronics, a computer is mostly a heater, as this experiment also confirms. The isobaric volumetric heat capacity of air in typical room conditions is 1210 J/(m3K) (Source).
A typical laptop processor is designed to dissipate somewhere around 50 Watts of heat at maximum, and at idle it sits somewhere around 15 Watts.
